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A 4.00 kg steel ball strikes a wall with a speed of 9 m/s at an angle of 60.0° with the surface. It bounces off with the same speed and angle (Fig. P8.9) If the ball is in contact with the wall for 0.200 s, what is the average force exerted on the ball by the wall?
F[tex]\Delta[/tex]T = [tex]\Delta[/tex]p
p = mv
[tex]\Delta[/tex]p = pf - pi = mvf - mvi = m(vf - vi)
[tex]\Delta[/tex]p = m(vf - vi)
[tex]\Delta[/tex]p = 4(-9 - 9)
[tex]\Delta[/tex]p = -72
Faverage[tex]\Delta[/tex]t = [tex]\Delta[/tex]p
Faverage(.2) = -72
Faverage = -360
Final answer is incorrect, any ideas?
F[tex]\Delta[/tex]T = [tex]\Delta[/tex]p
p = mv
[tex]\Delta[/tex]p = pf - pi = mvf - mvi = m(vf - vi)
[tex]\Delta[/tex]p = m(vf - vi)
[tex]\Delta[/tex]p = 4(-9 - 9)
[tex]\Delta[/tex]p = -72
Faverage[tex]\Delta[/tex]t = [tex]\Delta[/tex]p
Faverage(.2) = -72
Faverage = -360
Final answer is incorrect, any ideas?