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Homework Statement
Find an equation of the tangent line to x^3 + y^3 - 6xy = 0 at the point ((4/3), (8/3))
Homework Equations
I got y = -(8/5)x + (24/5). Is this correct?
The Attempt at a Solution
Lots of algebra involved. Sorry. but I'd rather not type it. I take the derivative of each term and eventually get:
[-3x^2 - 6y] / [3y^2 - 6x].
This simplifies to:
[x^2 + 2y] / [2x - y^2].
I substitute the stuff in appropriately, I get m = -(8 / 5).
Then I do:
y - (8/3) = -(8 / 5)(x - (4/3)).
I ask because Wolfram Alpha disagrees with me:
http://www.wolframalpha.com/input/?...3+++y^3+-+6xy+=+0+at+the+point+((4/3),+(8/3))