Motion in one dimension of a swimmer

In summary, in a relay race, the first swimmer has a 0.50-s lead and is swimming at a constant speed of 4.0 m/s. The second swimmer also moves at a constant speed and in order to catch up to the leader at the end of the pool, they must swim at the same speed for the remaining 50 m. This can be calculated using the formula V = D/T, where V is the speed, D is the distance, and T is the time. By determining the distance and time, the necessary speed for the second swimmer can be calculated.
  • #1
Alice-Shallom
4
0
Hi, i need help with the following:

One swimmer in a relay race has a 0.50-s lead and is swimming at a constant speed of 4.0 m/s. He has 50 m to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool?

I understand that since the 1st swimmer swims at constant speed, he has zero accelaration.

Is it useful to use this formula? Speed = Distance / Time
If not, which formula can i use?

Thanks.
 
Physics news on Phys.org
  • #2
Both swimmers swim at constant speeds. And, yes, V = D/T will be very useful.

Ask yourself: How much of a lead (in distance) does the first swimmer have? How long is the pool? How long will it take the first swimmer to reach the end?

Then ask: How fast must the second swimmer swim if he is to get all the way across the pool in the same time that the first swimmer takes to swim 50 m?
 
  • #3


To find the constant speed that the second swimmer must have in order to catch up to the leader, we can use the formula for distance: d = rt, where d is the distance, r is the rate (or speed), and t is the time. In this case, we know that the distance is 50 m and the time is 0.50 s for the first swimmer. Plugging these values into the formula, we get:

50 m = (4.0 m/s)t

Solving for t, we get t = 12.5 s.

Since the second swimmer needs to catch up to the leader at the end of the pool, their distance and time will be the same. We can set up a similar equation for the second swimmer:

50 m = (rs)t

Where r is the unknown speed of the second swimmer and s is the same time of 12.5 s. Solving for r, we get:

r = 4.0 m/s

Therefore, the second swimmer must also swim at a constant speed of 4.0 m/s in order to catch up to the leader at the end of the pool. This makes sense since both swimmers are covering the same distance in the same amount of time, they must have the same speed in order to reach the end at the same time.

In summary, we can use the formula d = rt to solve for the speed of the second swimmer, since they are both covering the same distance in the same amount of time. I hope this helps!
 

FAQ: Motion in one dimension of a swimmer

What is motion in one dimension?

Motion in one dimension refers to the movement of an object along a single straight line. It is also known as linear motion.

How does motion in one dimension apply to a swimmer?

In the context of a swimmer, motion in one dimension refers to their movement along a straight line in the water, such as swimming in a straight lane in a pool.

What factors affect the motion of a swimmer in one dimension?

The motion of a swimmer in one dimension can be affected by factors such as their body position, propulsion from strokes, and external forces such as water resistance.

How is speed calculated in one dimension motion?

Speed in one dimension is calculated by dividing the distance traveled by the time it takes to travel that distance. It is typically measured in units of distance per time, such as meters per second.

Can a swimmer's motion in one dimension be affected by external forces?

Yes, a swimmer's motion in one dimension can be affected by external forces such as wind, currents, and other swimmers in the water. These forces can cause the swimmer to change their speed or direction of motion.

Similar threads

Back
Top