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A worker works in a roof and let's a hammer fall over the roof with the speed 4m/s.The roof forms an angle 30 degree related to the horizon and its lowest point its 10meters from the ground.What is the horizontal displacement of the hammer from the moment he leaves the roof to the moment he touches the ground.
So X=Vox*t
I need to find that t.
Y=Voy*t +g*t^2/2
Y is 10 m ...what do I do now?
So X=Vox*t
I need to find that t.
Y=Voy*t +g*t^2/2
Y is 10 m ...what do I do now?