Motion on a Plane: Solving Problems with Stone Thrown from 200m Tower

In summary, the conversation discusses the problem of a stone being thrown with an initial horizontal velocity of 10m/s from a 200m high tower. The first question asks about the stone's position after 2 seconds, the second question asks when it will hit the ground, and the third question asks about its speed upon hitting the ground. The solution involves treating the x and y motions separately and then combining the results to answer the questions.
  • #1
mohammed1992
3
0
Question:
A stone is throws with an initial horizontal velocity of 10m/s form the top of a tower 200m high.
a)where is the stone 2 seconds after being thrown?
b)when will it hit the ground?
c)what is the speed upon hitting the ground?

(this is not my homework it a question that wasn't discussed in class and i am not able to answer it)
 
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  • #2


Thank you
 
  • #3
The trick is that the x and y motions are independent and are superimposed on each other (an approximation good for the world being flat). If it is thrown horizontally, then the initial velocity has no y component. First, solve a problem as thought there is only y-motion, that it, a stone dropped vertically from rest. Find the time to hit the ground, the position at 2 seconds, and the final speed just before it hits the ground. Then do another problem as if there is only x-motion, as if it were sliding on a table. Neglecting air resistance, x-motion has a constant horizontal velocity, because gravity doesn't affect the x-motion. Find the position at 2 seconds. Find the x-velocity at the time when the first part of the problem, the y-solution, said it will hit the ground. Now you can combine the x-results and the y-results to get the things they ask for.
 
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FAQ: Motion on a Plane: Solving Problems with Stone Thrown from 200m Tower

How do I calculate the speed of the stone thrown from a 200m tower?

To calculate the speed of the stone, we can use the formula v = √(2gh), where v is the speed, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the tower (200m). Plug in the values and solve for v to get the speed of the stone.

What is the maximum height the stone reaches during its flight?

To find the maximum height, we can use the formula h = (v²sin²θ)/(2g), where h is the maximum height, v is the speed of the stone, θ is the angle at which the stone is thrown, and g is the acceleration due to gravity. Plug in the values and solve for h to get the maximum height.

How long does it take for the stone to reach the ground?

The time taken for the stone to reach the ground can be calculated using the formula t = (vsinθ + √(v²sin²θ + 2gh))/g, where t is the time, v is the speed of the stone, θ is the angle at which the stone is thrown, and g is the acceleration due to gravity. Plug in the values and solve for t to get the time taken.

What is the horizontal distance traveled by the stone before hitting the ground?

The horizontal distance can be calculated using the formula d = vcosθ * t, where d is the distance, v is the speed of the stone, θ is the angle at which the stone is thrown, and t is the time taken. Plug in the values and solve for d to get the horizontal distance traveled.

How does air resistance affect the motion of the stone?

Air resistance can affect the motion of the stone by slowing it down and changing its trajectory. However, for this particular problem, we assume that air resistance is negligible due to the short distance and high speed of the stone.

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