- #1
mjolnir80
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Homework Statement
the question is like this :you are in a balloon that is rising at a rate of 3.0m/s . you have two rocks. you release one when you are 50m above the ground. 2 seconds later you throw the other rock towards the ground . the two rocks hit the ground at the same time . what was the initial velocity of the second rock (with respect to the ground)
Homework Equations
we have to solve it only using the simple motion equations such as:
∆d = Vi t + ½ a t2
The Attempt at a Solution
what i did was to first say that :
t(rock1)=t(rock2)-2s and we also know that the second rock is released when we are 56m above the ground
then i proceeded to calculate the time it takes for the first rock to hit the ground (considering the fact that Vi for the first rock is 0)
then i subtracted 2 from this time and used it to calculate Vi for the second rock
i used ∆d = Vi t + ½ a t2 to calculate both these things
the problem is I am not sure I am doing this right and i would appreciate it if someone could confirm my method
thanks in advance