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simondsaid
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Homework Statement
Picture: http://www.webassign.net/grr/p8-34.gif
A mountain climber is rappelling down a vertical wall. The rope attaches to a buckle strapped to the climber's waist 15 cm to the right of his center of gravity and makes an angle of [tex]\theta[/tex]= 19° with the wall. The climber weighs 744 N.
(a) Find the tension in the rope=680N
(b) Find the magnitude and direction of the contact force exerted by the wall on the climber's feet.
Magnitude=240N
Direction=[tex]\theta[/tex]=? above the horizontal.
Homework Equations
T=[tex]\frac{W*.91m}{1.06m*cos19}[/tex]
W=Tcos[tex]\theta[/tex]+F[tex]_{v}[/tex]
T*sin[tex]\theta[/tex]=F[tex]_{h}[/tex]
Magnitude F[tex]_{w}[/tex]=[tex]\sqrt{F^{2}_{v}+F^{2}_{h}}[/tex]
The Attempt at a Solution
The equations basically explain my attempt at the problem. I just can't seem to be able to find the direction of the contact force exerted by the wall.
I've tried:
arctan[tex]\frac{Fv}{Fh}[/tex]=25°