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soupastupid
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Homework Statement
m_1, v_1f
m_2, v_2f
m_2 = m_1 = m
Homework Equations
KE = .5mv^2
W = F*d
spring: F= -kx
pot energy = PE = -.5kx^2
The Attempt at a Solution
A) K + U = .5m(v_1f)^2 + .5m(v_2f)^2 - .5kx^2
.5(.1kg)(v_1f)^2 + .5(.1kg)(v_2f)^2 -.5(100N/m)(.02m)^2
B) ??
translational KE - going straight?
isnt it
.5(.1kg)(v_1f)^2 + .5(.1kg)(v_2f)^2
C) ??
V_cm...
??
am i looking for how fast the center of the spring is moving?
the center of the spring moved from .03 m to .1m
and so
?? I am lost
or do I get the average speed of the two boxes which would be
V_cm = (V_1f+V_2f)/2
or
.5(.1kg)(v_1f)^2 + .5(.1kg)(v_2f)^2 -.5(100N/m)(.02m)^2 = Wd = (5N)(.08m)
(v_1f)^2 + (v_2f)^2 = 8.4 (m^2)/(s^2)
does that equal V_cm?
V_cm = ( 8.4 (m^2)/(s^2) ) ^ (1/2) = 2.90 m/s
D) ??
vibrational?