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adorfy
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Homework Statement
Box 1 of mass m1 is attached by a thin rope to box 2 of mass m2. Box 1 is pulled by force F. What is the acceleration of box 1 given:
m1= 3kg
m2= 2kg
V(initial)= 4m/s
F= 50N
Friction is present between boxes and floor
μ = 0.2
θ = 20 degrees
∅ = 35 degrees
gravity(g) = 9.8
And what value would F need to be so the velocity is constant at 4.0 m/s
The Attempt at a Solution
I know that Fnet is going to be the x component of the force F minus the friction between box 1 and the ground and the x component of the tension on box 1 by box 2
Fnet = Fx-(Fμ+Ftx)
By plugging into equations I found
Fx = cos∅*F = 40.9576
Fy = sin∅*F = 28.6788
Fg = m*g = 29.4
N(normal) = Fg+ Fy+Fty=50.0788+Fty
Fμ = N*μ=μ(Fg+Fy+Fty)=0.2(50.0788+Fty)
Fnet =Fx-(Fμ+Ftx)=40.9576-(0.2(50.0788+Fty)+Ftx)
I just can't find Ft
I initially tried that Fty=m2gsinθ and Ftx=m2gcosθ bur this was marked wrong