Multiplying by unit vector in electric field equation

In summary, two point charges, 5.0 μC and -4.0 μC, are located at specific coordinates. The magnitude and direction of the electric field at a given point is to be found, as well as the force on a proton at that same point. The equation E = (kq/r²) x [r-hat] is used, where r-hat represents a unit vector. The steps to solve for the electric field and force involve finding the distances between points, calculating the slope and angle, resolving components, and finding the sum of the electric fields.
  • #1
ChrisBaker8
24
0

Homework Statement



A 5.0 μC point charge is located at x = 1.0 m, y = 3.0 m, and a −4.0 μC point charge is located
at x = 2.0 m, y = −2.0 m.

a) Find the magnitude and direction of the electric field at x = −3.0 m, y = 1.0 m. [5 Marks]
b) Find the magnitude and direction of the force on a proton at this position in a).

Homework Equations



E = (kq/r²) x [r-hat] (couldn't find the symbol for r circumflex)

The Attempt at a Solution



I can work out the first part of the equation, but I'm unsure what r-hat represents and what figure to use. I thought a unit vector was in the form Ai + Bj + Ck, how do you multiply that by a figure to get another single figure?
 
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  • #2
Let point A be ( 1 m, 3 m) and point B be (2 m, -2 m). Let P be the point (-3 m, 1 m) where you want to find the electric field.
First of all find the distances AP and BP. Finding slope of the line AP and BP, you an find the angle made by the electric fields with x-axis. Then resolve them along vertical and horizontal components. Then find ΣEx and ΣEy and E.
 
  • #3


As a scientist, it is important to understand the concept of unit vectors in relation to electric fields. In the electric field equation, the unit vector [r-hat] represents the direction of the electric field at a specific point. It is a vector with a magnitude of 1 and points in the direction of the electric field.

To answer the first part of the question, you can use the given equation and plug in the values for the charges and their positions. Then, you can use the properties of unit vectors to find the direction of the electric field at the given point. The magnitude of the electric field can be calculated using the distance between the point charges and the distance between the point charge and the given point.

For the second part of the question, you can use the equation F = qE, where q is the charge of a proton and E is the electric field calculated in part a). This will give you the magnitude of the force on the proton. To find the direction of the force, you can use the right-hand rule, where the direction of the force is perpendicular to both the electric field and the velocity of the proton.

It is important to note that the unit vector [r-hat] is used to represent the direction of the electric field, not to multiply by a figure to get another single figure. It is a mathematical tool used to simplify calculations and represent the direction of a vector. I hope this helps clarify the concept of unit vectors in the electric field equation.
 

FAQ: Multiplying by unit vector in electric field equation

What is a unit vector in the context of electric fields?

A unit vector is a vector with a magnitude of 1 and is used to specify a direction in three-dimensional space. In the context of electric fields, unit vectors are often used to represent the direction of the electric field at a specific point.

How do you multiply by a unit vector in the electric field equation?

To multiply by a unit vector in the electric field equation, you simply multiply the magnitude of the electric field by the unit vector in the direction of interest. This will give you the component of the electric field in that direction.

Can you explain the significance of multiplying by a unit vector in the electric field equation?

Multiplying by a unit vector in the electric field equation allows us to break down the electric field into its individual components. This is useful in understanding the strength and direction of the electric field at a specific point.

What are the units of the product of the electric field and unit vector?

The units of the product of the electric field and unit vector will depend on the units used for the electric field. However, it is important to note that the unit vector itself has no units since it is a direction rather than a physical quantity.

How does the direction of the unit vector affect the result of the multiplication in the electric field equation?

The direction of the unit vector will determine which component of the electric field is being calculated. Multiplying by a unit vector in the x-direction will give the x-component of the electric field, while multiplying by a unit vector in the y-direction will give the y-component, and so on.

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