Multivariable class, we'll be starting curvature

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The discussion centers on the challenges of understanding curvature in a multivariable calculus class. The original poster expresses frustration with the concept and the teaching quality, indicating a need for self-study. They mention the curvature formula \kappa=|d\phi/ds| and struggle with finding an appropriate equation for \phi. A more manageable equation, \kappa=\frac{|\mathbf{r}'\times\mathbf{r}''|}{|\mathbf{r}'|^{3}}, is introduced, which simplifies the calculations. The conversation highlights the importance of finding clearer resources and methods for grasping complex mathematical concepts.
FluxCapacitator
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Next week in my multivariable class, we'll be starting curvature, and, nerd that I am, I looked ahead to learn it ahead of time. I can usually at least understand the basics of a new concpet by myself, but curvature really threw me off. Maybe my brain's not right for it, maybe the book sucks, but I know my teacher sucks, so I'm pretty much going to have to learn it myself.

I know that curvature is \kappa=|d\phi/ds|, where \phi is the angle between the curve's tangent vector and the horizontal, and s is the arc length.

I also get that the way to do this is to make it \kappa=|d\phi/dt/(ds/dt)|, I get lost, however, in actually finding a good equation for \phi.

Does anyone have any tips, resources, or advice?
 
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From what I've learned, that equation is hard to work with. Have you seen it as this?:

\kappa=\frac{|\mathbf{r}'\times\mathbf{r}''|}{|\mathbf{r}'|^{3}}

It's much easier to work with (r is the position vector). To show that the two definitions are equal, use the following fact:

\mathbf{r'}=\frac{ds}{dt}\mathbf{T}
 
That's a lot better :D . Thanks! That actually makes sense in a twisted sort of way, and it's a lot easier to use.
 

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