- #1
curiousburke
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- TL;DR Summary
- Does calculating the distance traveled by a muon (L' in the muons frame), using two equations for length contraction (one at each end point) to eliminate delta t and solve for L' in terms of L and gamma lead to a contradiction?
I'm having a discussion with a friend/family member about a paper by Radwan Kassir in which he calculates the distance traveled by a muon (atmosphere thickness) in a non-standard way that shows the atmosphere thickness in the muons frame (L') is γ times the atmosphere thickness in the Earth frame (L), which of course conflicts with the standard approach that results in L' = L/γ.
The basic idea is that you can use two equations for Δx' at two different places (both of which equal L'), eliminate Δt, and solve for L' in terms of γ and L, which is Δx. First, calculate Δx' of the muon = γ × ( Δx(muon) - v Δt ) in which Δt is the time between creation and hitting the Earth in the Earth frame. In the muons frame Δx'(muon)=0, so Δx(muon) = v Δt. Second, calculate Δx' of the Earth = L' = γ × ( Δx(Earth) - v Δt). In this case, Δx(Earth)=0, so L' = γ × ( -v Δt). From the first eqn vΔt = -Δx(muon)=L, so L' = -γ × L.
Okay, I got a sign error, but the idea is the same. What is happing here to show this contradiction, and how is it resolved?
The basic idea is that you can use two equations for Δx' at two different places (both of which equal L'), eliminate Δt, and solve for L' in terms of γ and L, which is Δx. First, calculate Δx' of the muon = γ × ( Δx(muon) - v Δt ) in which Δt is the time between creation and hitting the Earth in the Earth frame. In the muons frame Δx'(muon)=0, so Δx(muon) = v Δt. Second, calculate Δx' of the Earth = L' = γ × ( Δx(Earth) - v Δt). In this case, Δx(Earth)=0, so L' = γ × ( -v Δt). From the first eqn vΔt = -Δx(muon)=L, so L' = -γ × L.
Okay, I got a sign error, but the idea is the same. What is happing here to show this contradiction, and how is it resolved?