Muonic hydrogen, change in potential of the muon.

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The discussion focuses on calculating the change in potential experienced by a muon in muonic hydrogen when comparing a uniformly charged proton to a point-like proton. It highlights that while the electric field outside the proton remains unchanged, the potential differs inside the proton due to the muon's wave function having a non-zero probability at the origin. This necessitates the use of first-order perturbation theory to account for the energy shift in the ground state. The key insight is that the perturbation only affects the region inside the proton, leading to a finite change in potential. Understanding this distinction is crucial for accurately calculating the energy shift in muonic hydrogen.
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Homework Statement



Taking the proton to be a uniformly charged sphere of radius 1 fm, find an
expression for the change in potential experienced by the muon as compared with that
in the case of a point-like proton. Use first order perturbation theory to calculate the
ground-state energy shift in muonic hydrogen



Homework Equations



E=-grad(V)

The Attempt at a Solution



The electric field due to a uniformly charged sphere is exactly the same as the field due to a point charge of the region outside the sphere (by a simple application of gauss's law). For this reason I see no need for the potential to change. What am I missing?
 
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What you say is true - the potential outside of the proton is unchanged. However, the potential inside the proton is different in the two cases. Since the wave function at the origin is non-zero, there is some finite probability for the muon to be found inside the proton. So you can take the standard 1S solution as the unperturbed state, and apply a perturbation which is a difference between the potential of a point charge and the potential of a sphere. The perturbation is only non-zero inside the proton.
 
Thanks. That makes sense.
 

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