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Homework Statement
http://img265.imageshack.us/img265/8616/43354308.png
I have an exam coming up in a few days and I am doing some revision questions from some past exams and this is one I have attempted but I have no solutions to check my answers.
The Attempt at a Solution
using Vs = 12cos( 1000t - 90degrees)
and w = 1000 I have transformed the circuit into their complex impedances
Vs ~= 5.3 + 10i
C1 = -4i
L1 = 5i
L2 = 6i
LM = 3i
R1 = 12a) Z22 = 6i+12
b) (W^2 * M^2)/Z22 = Zr
As W = 1000 and M = 3i
Zr = 0.6 - 0.3i
c) Zr + L1 + ZC = 0.6 + 1.3i
d & e)
Calculating the currents I1 and I2.
Using these equations for the loops:
Loop1: -vs + (Zc + L1)I1 - LM*I2 = 0
Loop2: L2I2 + 12 - LMI1 = 0
Loop1: I1 = -4i + 2I2
Loop2 subbing I1 in I2 = 2 - 1.86i
Hence I1 = 4 - 7.2i
edit: I know I made a mistake with the algebra above but if I use KVL is that formula correct?
Could someone verify that these answers are correct or that I am at least using the correct method?
f)
V = IR
Vout = (2-1.86i)12
Vout = 24 - 22.32i
Vout = 32cos(1000t - 42degrees)
g)Transformer has a step up effect as the magnitude of Vout is greater than that of Vs. Also, as the magnitude of I2 is less than that of I1 it seems logical to expect a greater voltage if the current is lower.
32 > 12
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