- #1
jokiemay
- 18
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Im about to hand coursework in. Its the youngs modulus of copper wire
We added 100g weights and measured the extension using a traveling microscope.
for example at 0.900kg the wire extended by 6.36cm
my calculations are
Diameter = d 2.7x10-5 m
Cross section area A = Pi x d (squared) /4 = 5.7 x 10-8
Applied Force F = (mxg) 0.900 x 9.81 = 8.82 kg m s-1
Extension e = 0.0636 m
Original length L = 1.788 m
So Stress = F/A = 1.54 x 10(8)
Strain = E/L = 3.6 x 10-2
Stress / Strain = Youngs modulus E = 42 x 10(8) Pa
Does this look correct?
If i was to work out my mass / extension from my graph i would get this ...
m/e = 14.2 x (gxL) 17.5 / A 5.73 x 10-8 = 4.3 x 10(9) pa
We added 100g weights and measured the extension using a traveling microscope.
for example at 0.900kg the wire extended by 6.36cm
my calculations are
Diameter = d 2.7x10-5 m
Cross section area A = Pi x d (squared) /4 = 5.7 x 10-8
Applied Force F = (mxg) 0.900 x 9.81 = 8.82 kg m s-1
Extension e = 0.0636 m
Original length L = 1.788 m
So Stress = F/A = 1.54 x 10(8)
Strain = E/L = 3.6 x 10-2
Stress / Strain = Youngs modulus E = 42 x 10(8) Pa
Does this look correct?
If i was to work out my mass / extension from my graph i would get this ...
m/e = 14.2 x (gxL) 17.5 / A 5.73 x 10-8 = 4.3 x 10(9) pa
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