Natural Frequency Question SI Units

In summary: Bob SIn summary, the natural frequency of a mass-spring system with constant k and no damping is given by the formula w_n=sqrt(k/M), with units of radians per second. This is because the solution to the governing differential equation is in terms of angular measure, and radians are the natural numbers that result from this expression. While frequency can also be measured in cycles per second (Hz), it is important to note that 1/s can represent either Hz or rad/s. This can lead to confusion, as seen in the case of the system's time constant tau, which has units of seconds but is related to the s plane in rad/s. However, this is simply a matter of carrying around factors of 2π
  • #1
yanaibarr
6
0
i have a basic question about the natural frequency of a system.
for a mass (M), spring (k constant) undamped system the natural frequerncy is:
w_n=sqrt(k/M)
the units of w_n according to a lot of resources i found on the internet & textbooks are [rad/sec], my question is why?
if i use the k constant units divided by the mass i get [Hz]:
[k]/[M]=[N/m]/[kg]=[kg*m/s^2*m]/[kg]=[1/s^2]
[w_n]=sqrt([k]/[M])=[Hz]

i'll appreciate a clarification in this subject.

thanks.
 
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  • #2
Hello yanaibarr, welcome to Physics Forums

Radians are used because the solution to the governing differential equation is in terms of angualar measure y = Asin(x-ct) and radians (not degrees), being the natural numbers you obtain from such an expression.
 
  • #3
yanaibarr said:
if i use the k constant units divided by the mass i get [Hz]:
[k]/[M]=[N/m]/[kg]=[kg*m/s^2*m]/[kg]=[1/s^2]
[w_n]=sqrt([k]/[M])=[Hz]
Actually you got 1/s, not Hz, for the units. You are assuming that 1/s always means Hz (= cycles/s), but that is not always the case.

Frequency can be measured in rad/s or cycles/s. Both radians and cycles are considered unitless, so both types of frequency can show up as 1/s if you use an equation to figure out the units.
 
  • #4
Actually, Hz is exactly 1/s, and nothing else.

And radians are units to measure angles and represents a very well defined fraction of a revolution...a radian is the angle that you can measure at the center of a circle between two radial lines (from the center to the circle's circumference) whose distance between the two tips of the radii along the perimeter of the circle is again the length of the radius itself...I think this came out rather convoluted...google it, I am sure you will get a nice picture, somewhere.

Needless to say, pi (3.1415926) has the definition of how many times the diameter of a circle fits along the circumference of the circle itself...see the relation? the diameter fits 3.1416 times along the circumference, and so the radius fits twice as many times...6.2832, that means that a radian spans an angle of 360/6.2832 = 57.29 degrees

So, when you are talking about angular velocity or angular frequency in radians per second, there is a straight relationship between radians per second and revolutions per second (or 1/s)...so, if you have something going at 1 revolution per second (1/s or Hz) is also going at 6.2832 radians per second (rad/s).

Conversely, if you have something going at 1 radian per second, it is also going at 1/6.2832 revolutions per second or 0.159 Hz.
 
  • #5
gsal said:
Actually, Hz is exactly 1/s, and nothing else.
Yes, but 1/s could mean either Hz or rad/s. That was my point. The frequency calculated from the [itex]\sqrt{k/m}[/itex] formula has units of 1/s, but is in rad/s, not Hz.
 
  • #6
thank u for the answers.
But there is still one thing that bothers me,
if i have a first order system the basic transfer function will be:
K/(tau*s+1)
where K is the Gain, and tau is the system's time constant.
tau's units, according to what I've learned, are [sec].
but aren't the s plane units in [rad/sec] (s=jw+sigma)?
That means that tau should be given in [sec/rad] to match the "1" in the transfer function.
I know that rad can be considered "unitless" but when dealing with actual numbers it matters if the system's time constant is 1 [sec] or 1[sec/rad]= 2*pi [sec].

again, i'll appreciate a clarification.

Thanks
 
  • #7
If you go back to the basic physics equations:

1) F = -kx
2) m d2x/dt2 = -kx
3) d2x/dt2 = -(k/m) x
4) Substitute a solution x(t) = A sin(ωt) + B cos(ωt)
5) Find ω2 = k/m

Note that ω has units radians per second.

Bob S

Added: The SI units for one complete rotation through 4 quadrants is 2pi (2 π) radians. 360 degrees is NOT an SI unit.
 
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  • #8
In step 4 one could substitute a solution in the form x(t) = A sin(2πft) + B cos(2πft), and then step 5 would have (2πf)^2 = k/m and so on...

It just depends what solution form is substituted and whether one like carrying around factors of 2π in the math. (And it often leads to confusion, at least for me!)
 

FAQ: Natural Frequency Question SI Units

1. What are natural frequency questions?

Natural frequency questions refer to questions that involve determining the frequency at which a system or object naturally vibrates or oscillates. This frequency is determined by the physical properties of the system or object.

2. How do you calculate natural frequency?

Natural frequency can be calculated using the formula f = (1/2π) √(k/m), where f is the natural frequency, k is the spring constant, and m is the mass of the object or system. This formula applies to simple harmonic motion systems.

3. What are SI units?

SI units (Système International d'Unités) are the modern metric system of measurement used in science, technology, and everyday life. They are based on seven base units: meter (length), kilogram (mass), second (time), ampere (electric current), kelvin (temperature), mole (amount of substance), and candela (luminous intensity).

4. How are natural frequency questions related to SI units?

Natural frequency questions often involve determining the frequency of an object's oscillation, which is measured in hertz (Hz). Hertz is the SI unit of frequency and is defined as one cycle per second. In addition, the physical properties used to calculate natural frequency, such as mass and spring constant, are also measured in SI units.

5. What are some real-world applications of natural frequency questions?

Natural frequency questions have many real-world applications, including determining the resonant frequency of musical instruments, designing earthquake-resistant buildings, and predicting the behavior of bridges and other structures under different loads. They are also used in fields such as mechanical engineering, acoustics, and seismology.

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