Navier-stokes and 1 million dollars

In summary, the problem with solving the Navier-Stokes equation is that it is a tensor equation in need of scalar solutions. Pressure is a scalar but it is difficult to define. There are difficulties in solving the equation for a vortex because it is a vector field. It is complicated to solve and can give headache to those who study fluid dynamics.
  • #1
kurious
641
0
Help me find solutions for the Navier-stokes equations and you could get rich.
The problem is this:
A fluid enters a pipe and flows through it smoothly at the outset.
Will it keep flowing smoothly?
Sounds easy to solve but it isn't because nobody has
won the million dollars yet.

Here is one idea for how to deal with the problem:

Assume the equations which describe smooth flow are really the sums of two types of other equation describing vortices:
one set of equations about a vortex spinning clockwise and moving along the pipe, and the other set about a vortex spinning anticlockwise and also moving along the pipe.
The Navier-Stokes question then becomes:
Do the vortices cancel each other out permanently as time goes on?
 
Physics news on Phys.org
  • #2
Make a pipe with an inner frictionless surface

problem solved
 
  • #3
Safe bet by NS. The vortices will never cancel out. Even in a frictionless tube, there will always be swirls due to quantum effects.
 
  • #4
Tensor equations in need of scalar solutions

The Navier-Stokes equation is really a tensor equation in need of scalar solutions.

[tex] \frac{\vec{F}}{V} = - \vec{\nabla} P [/tex]

The major difficulty of its solution is the fact that the pressure term, P, is believed to be a scalar. If pressure is defined as Force per unit area, how could it be a scalar? Unless pressure is the scalar product of two vectors. It's obvious that force is always a vector or tensor but is 1/area a vector?

Macroscopically, pressure is a scalar. It is the average force that a bounding closed volume received on a point of its control surface. Once there is a hole on this closed surface, the definition of pressure becomes invalid.

But by taking the negative gradient of pressure, one inadvertently created a preferred direction for the pressure force and change the macroscopic model into a microscopic one. Hence, it is changed from a continuum dynamic to a discrete quantum problem.

Nevertheless, Navier-Stokes equations remain a fundamental model of classical mechanics not quantum mechanics. It remains just a continuum model of Newton's laws of motion. And the gravity law is proven correct only to a tenth of a millimeter.
 
Last edited:
  • #5
kurious said:
Do the vortices cancel each other out permanently as time goes on?

At the quantum level, these vortices do not cancel. I think, these are the spin component of each atom and even molecules have spin components.
 
  • #6
What if we have a low air pressure in the outset's side?
 
  • #7
In fiber optics, the problem of losses, I think, was solved by total internal reflection of light as waves not as particles.
 
  • #8
The theory of specific heat is based on the idealization of defining what is pressure as force per unit area. And the ideal triangular area is found to be the equilateral triangle whose area is [itex]1/2 \sqrt{3}[/itex] giving the ratio of hypotenuse to altitude as [itex]\frac{\sqrt{3}}{2}[/itex] whose twice square gives 3/2 instead of 5/2, an important factor in the kinetic theory of heat. But the 5/2-triangle is based on 1/2 unit area of an isosceles triangle whose base and altitude are equal to 1 but making the other side as inverse of its altitude whose magnitude is [itex] \frac{2}{\sqrt{5}}[/itex].
 
Last edited:
  • #9
Antonio Lao said:
At the quantum level, these vortices do not cancel. I think, these are the spin component of each atom and even molecules have spin components.
Chronos said:
Safe bet by NS. The vortices will never cancel out. Even in a frictionless tube, there will always be swirls due to quantum effects.
The "Million-Dollar-Problem" is purely mathematical and does not deal with physical reality at such a low scale. Of course there is no such thing as a non-smooth velocity field in a real liquid.
 
  • #10
kuengb said:
Of course there is no such thing as a non-smooth velocity field in a real liquid.

The velocity field of an ideal fluid is composed of massless field points which is a true continuum but real fluid is not so that a real fluid field point is associated with the electronic energy, the vibrational energy, the rotational energy, the translational energy.

Furthermore, to make NS equation soluble, the assumption that the pressure and temperature are constants is made and also that the divergence of the velocity is zero as in an incompressible fluid.
 
Last edited:
  • #11
What is the equation for a vortex?
What makes a vortex grow, what makes it shrink?
 
  • #12
kurious said:
What is the equation for a vortex?

I think it is the curl of a vector field, curl A or [itex] \nabla \times A [/itex]. It grows, assuming the vector is constant, to a maximum when the angle between the curl and the vector is an odd integer multiple of 90 degrees or pi/2.
 
Last edited:
  • #13
The answer is a bit complicated. It starts with the Helmholtz vortex theorems. It gets ugly after that. Fluid dynamics give me a headache.
 
  • #14
Anyone know of a good set of notes on fluid dynamics, I think i'll set to work on the problem right now. :approve:
 

Related to Navier-stokes and 1 million dollars

1. What is Navier-Stokes?

Navier-Stokes is a set of equations that describe the motion of fluids, including liquids and gases. They were first developed in the 19th century by Claude-Louis Navier and George Gabriel Stokes.

2. How are Navier-Stokes equations used in science?

Navier-Stokes equations are used to study and predict the behavior of fluids in various systems, such as in aerodynamics, weather forecasting, and oceanography. They are also used in the design and optimization of machines and structures that involve the movement of fluids.

3. Why are Navier-Stokes equations important?

Navier-Stokes equations are essential in understanding the fundamental principles of fluid mechanics and have numerous practical applications in engineering and science. They are also used as a benchmark for testing the accuracy of computational fluid dynamics models.

4. What is the significance of 1 million dollars in relation to Navier-Stokes?

The Clay Mathematics Institute offers a $1 million prize for anyone who can solve the Navier-Stokes equations, which are notoriously difficult to solve analytically. This prize is part of the Millennium Prize Problems, a set of seven unsolved problems in mathematics.

5. Has anyone ever solved the Navier-Stokes equations and claimed the million-dollar prize?

No, as of 2021, the Navier-Stokes equations remain an unsolved problem, and the Clay Mathematics Institute has not awarded the prize to anyone. However, progress has been made in developing numerical methods for approximating solutions to these equations.

Similar threads

  • Other Physics Topics
Replies
2
Views
1K
  • Differential Equations
Replies
3
Views
562
Replies
9
Views
2K
Replies
18
Views
1K
Replies
2
Views
3K
  • Mechanical Engineering
Replies
14
Views
6K
Replies
3
Views
2K
Replies
20
Views
5K
Replies
2
Views
1K
Replies
1
Views
2K
Back
Top