- #1
WannaBe
- 11
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Prove that for any two numbers x,y we have [(x^2 + y^2)/2] >= x + y - 1
Solution)
For any number a we have have a^2 > 0. So,
(x-1)^2 + (y-1)^2 >= 0
And if we solve this we get the solution.I don't get the red part.
Solution)
For any number a we have have a^2 > 0. So,
(x-1)^2 + (y-1)^2 >= 0
And if we solve this we get the solution.I don't get the red part.