Need Help CMOS signal divider cuircuit

[steelaustin]

Hey i need help configuring a CD4059A cmos made by Texas Instruments to divide an input signal by 100x. any Tips or schematics would be awsome
here's a link to the data sheet of the CD4059
http://www.ortodoxism.ro/datasheets2/4/08zpgqfhxjjawz4y7id14ph596py.pdf


Thanks
steelaustin

 

[berkeman]

The datasheet seems pretty clear and complete. What specific questions do you have? Also, if this is for homework/coursework, I can move the question to the Homework Help forums.

Welcome to the PF, BTW.

 

[steelaustin]

Im having trouble understanding the data sheet. I need to know how to hook it up like schematics or something.
No this isn't coursework its just a project I am working on for my car!
Thanks,
steelaustin

 

[steelaustin]

Please anyone i have the parts i just need some pointers on either how to set it up or on how to figure out how to set it up. I got the data sheets but i got no idea what I am looking at Please Help!

 

[berkeman]

I googled CD4059A tutorial, and got a couple good hits. See if this hit will help you out:

CD4059A App Note: http://server.oersted.dtu.dk/ftp/da...ig_Resource_1997/data/an/an6/an6374/index.htm

 

[steelaustin]

That website is dated 1995 that company has been out of the buissness for over 10 years so the information is no longer available however i googled "CD4059A help" and found this in another forum but i still need to make sense of it.

At power up you have to follow next procedure to setup a certain counting mode and divider into the 4059.

1) With no power to the circuit set the 16 jam inputs J1 to J16 at a correct level depending on your divider.
1a) Let say you have a divider of 5070 and want to use the divide by 4 mode.
1b) Calculate the divider to set into the counter: 5070 / 4 = 1267 remainder 2
1c) Jumper setting:
J1: remainder "1" = 0 remainder = 2
J2: remainder "2" = 1
J3: divider "1" * 10E3 = 1 thousands of divider = 1
J4: divider "2" * 10E3 = 0
J5: divider "1" * 10E0 = 1 units of divider = 7
J6: divider "2" * 10E0 = 1
J7: divider "4" * 10E0 = 1
J8: divider "8" * 10E0 = 1
J9: divider "1" * 10E1 = 0 tens of divider = 6
J10: divider "2" * 10E1 = 1
J11: divider "4" * 10E1 = 1
J12: divider "8" * 10E1 = 0
J13: divider "1" * 10E2 = 0 hundreds of divider = 2
J14: divider "2" * 10E2 = 1
J15: divider "4" * 10E2 = 0
J16: divider "8" * 10E2 = 0

2) Set all inputs Ka, Kb and Kc to a low level. Enable the "Master Preset Mode"

3) Apply power to the circuit

4) Apply at least three clock pulses on CP input

5) Set inputs Ka, Kb and Kc at a correct level according to the used "divide by" mode. For divide by 4 mode Ka low, Kb and Kc high

That sequence is implemented by the gates in the "Logic.jpg" file.
Set the 16 jumpers with no power to the circuit, then apply power.
Wire i is low for at least 3 clock pulses from wire g. After that it has a high level setting the counter in de divide by 4 mode.

IC4 makes 50Hz pulses from 24Vac after transformer. That is my counting frequency.
During normal operation I need to count only when there is 24Vdc across D3 but since I need at least 3 pulses to setup the divider I made an OR gate with D4 and D5. Set up via D5, normal operation via D4.

Attached Images

 

[steelaustin]

i also found this schematic do you think this will work?

 

[berkeman]

It looks like that schematic is using a 1/1000 tap. Is there a 1/100 tap also available to give you what you originally asked for?

 

[steelaustin]

oh I am sorry that /100x is a typo its supposed to be 1/1000 so this will work then the only reason I am scheptical about this setup is because i found another schematic that involved a tonn of diodes and other components to make it work properly but this is way easier to do. so Thanks for your help let's see if this thing can run my car!

 

[steelaustin]

oh wait yea the other one I am talking about i already posted lol

 

[billblack]

No offense, but:
Asking vague questions is a sure-fire way to minimize the amount of interest shown in your problem. I would suggest you remember that you are asking people to give up some of their time and mental energy to help you. Therefore, if you pose your question in an interesting way and describe what the circuit in question is supposed to do, then I'd bet you'll get more help.

 

[steelaustin]

yea your right thanks il take that into account next time.

 

[steelaustin]

Thank you all for the Help the unit fuctions properly and produces 3x as much hydrogen/oxogen than conventional electrolosis without useing nearly as much current! Thankyou.