Need help in determining the lim

  • Thread starter Thread starter Equilibrium
  • Start date Start date
Equilibrium
81
0
Hi

\lim_{x\rightarrow 4}\frac{x^2 - 3x + 4}{2x^2 - x - 1}

this is lim x ->4 which is the cube root of the whole fraction ^

Is there any way to answer this because i can't really factor it...
 
Last edited:
Physics news on Phys.org
Why not just evaluate the limit at x = 4?
 
You don't need to factor it. It can easily be factored, since it's a ratio of quadratic polynomials.

Daniel.
 
Assuming f(x) is continuous at f(a) (\lim_{x \rightarrow a^{+}} f(x) = f(a) =\lim_{x \rightarrow a^{-}} f(x)) you can always just plug in a. The only time you would need to factor is if f(x) is not continuous at a or if plugging in a would result in an undefined function (0 in denominator). So yea, as courtigrad said, just substitute x=4. :-)
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply . Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top