- #1
jono240
- 11
- 0
There is a crucial aspect of this unit that I am not understanding and that is how to find how many nodal or anti nodal lines are in the equation.
relevant formulas:
So if I am looking for how many anti nodal lines exist I use the formula | dsinθmax = n*λ |
So let's say I have d and λ
d = 51cm and λ = 4
So we need to solve for n
1. Now on the board, the teacher will write the formula | dsinθmax = n*λ |
2. from there we get | sinθmax = (n*λ) / d | which cannot be greater than 1.
3. so | (n*λ) / d ≤ 1 |
4. then we get | n ≤ (d / λ) |
5. n = (51 / 4)
6. n = 12.75
then you get the answer for n.
I just don't get at all how you get from 3. to 4. algebraically
i really need this cleared up. I need to understand how that works. I hope someone can explain it to me
thanks
relevant formulas:
So if I am looking for how many anti nodal lines exist I use the formula | dsinθmax = n*λ |
So let's say I have d and λ
d = 51cm and λ = 4
So we need to solve for n
1. Now on the board, the teacher will write the formula | dsinθmax = n*λ |
2. from there we get | sinθmax = (n*λ) / d | which cannot be greater than 1.
3. so | (n*λ) / d ≤ 1 |
4. then we get | n ≤ (d / λ) |
5. n = (51 / 4)
6. n = 12.75
then you get the answer for n.
I just don't get at all how you get from 3. to 4. algebraically
i really need this cleared up. I need to understand how that works. I hope someone can explain it to me
thanks
Last edited: