- #1
dapias09
- 29
- 0
Hello, I need help with a very hard integral, I was trying several steps and I tried in the software "derive" but the answer didn't like to me.
It is ψ(x,t)= [b^2-(x-vt)^2]^(-2) . I must integrate it with respect to x .
Thanks in advance for any help!
PD: I tried x-vt = u like the first step du=dx. My teacher adviced to me continue with [b^2-u^2]^(-2) = z but I don't know how to continue in the best way.
It is ψ(x,t)= [b^2-(x-vt)^2]^(-2) . I must integrate it with respect to x .
Thanks in advance for any help!
PD: I tried x-vt = u like the first step du=dx. My teacher adviced to me continue with [b^2-u^2]^(-2) = z but I don't know how to continue in the best way.