- #1
shamieh
- 539
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When dealing with this separable equation for example, if I'm told to solve the given D.E.
$y' = x^2/y$
so after manipulation and taking the integral I got $\frac{y^2}{2} = \frac{x^3}{3} + C$ This is the implicit form correct?
Would the explicit form be $y = \sqrt{\frac{2}{3} x^3 + C}$
$y' = x^2/y$
so after manipulation and taking the integral I got $\frac{y^2}{2} = \frac{x^3}{3} + C$ This is the implicit form correct?
Would the explicit form be $y = \sqrt{\frac{2}{3} x^3 + C}$