- #1
Ninjamonkey474
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1. A 1000 kg automobile initially moving 72 km/h jams the brakes and skids to a stop in a distance of 24 m on a dry pavement but stops in 81.6 m for a wet pavement. (Neglect reaction delay.)
A. Calculate the applied forces for both weather conditions.
B. What is the coefficient of friction for dry weather?
C. What is the coefficient in wet weather conditions
2. Vfinal2=V02-2ad,
μ=Ffriction/Fnormal,
F=ma
3. I said this was impossible since both friction and applied are pointing in the same direction, you can only calculate the net force and not the applied, without which you cannot find either of the coefficients. She said it was possible but I didn't understand what she meant, can somebody explain to me why I'm wrong or why I'm right?
A. Calculate the applied forces for both weather conditions.
B. What is the coefficient of friction for dry weather?
C. What is the coefficient in wet weather conditions
2. Vfinal2=V02-2ad,
μ=Ffriction/Fnormal,
F=ma
3. I said this was impossible since both friction and applied are pointing in the same direction, you can only calculate the net force and not the applied, without which you cannot find either of the coefficients. She said it was possible but I didn't understand what she meant, can somebody explain to me why I'm wrong or why I'm right?