- #1
StephenDoty
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Two positive charges q0 at the origin and q1 at (0,d1,0) and one negative charge -q2 at (0,d2,0). What is the net force on particle 0 from particle 1 and 2? (See Picture CPartB inserted at bottom)
F on 0 due to 1 = kq0q1/d1^2 and since it is in the negative y direction since q1 repels q0 wouldn't F on 0 due to 1 = -kq0q1/d1^2 [tex]\hat{y}[/tex]?
F on 0 due to 2 = kq0q2/d2^2 and since it is in the positive y direction since q2 attracts q0 wouldn't F on 0 due to 2 = kq0q2/d2^2 [tex]\hat{y}[/tex]?
So wouldn't the net force = -kq0q1/d1^2 [tex]\hat{y}[/tex] + kq0q2/d2^2 [tex]\hat{y}[/tex]? Would this be the way I type it into mastering physics?
Thank you for your help. I am having a difficult time figuring out how to input my answers in Mastering Physics.
Stephen
F on 0 due to 1 = kq0q1/d1^2 and since it is in the negative y direction since q1 repels q0 wouldn't F on 0 due to 1 = -kq0q1/d1^2 [tex]\hat{y}[/tex]?
F on 0 due to 2 = kq0q2/d2^2 and since it is in the positive y direction since q2 attracts q0 wouldn't F on 0 due to 2 = kq0q2/d2^2 [tex]\hat{y}[/tex]?
So wouldn't the net force = -kq0q1/d1^2 [tex]\hat{y}[/tex] + kq0q2/d2^2 [tex]\hat{y}[/tex]? Would this be the way I type it into mastering physics?
Thank you for your help. I am having a difficult time figuring out how to input my answers in Mastering Physics.
Stephen