- #1
JK423
Gold Member
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Hello, i'd really need some help with the following questions.
1) Neutral Pion
It's quark content is written as: [tex]\pi^0=(u\overline{u}-d\overline{d})/\sqrt{2}[/tex]
But the u-quark have a (quite) different mass than the d-quarks. This means that the neutral pion is a superposition of states of different mass??
2) Right-Handed (RH) Neutrinos
First of all, I am talking about SM neutrinos with zero mass! We know that neutrinos interact only via the weak interactions and only with their Left-Handed (LH) component. So, the theory actually predicts that we cannot observe RH neutrinos. Does this mean that they do not exist? I ask this because my proffessor made that assertion, and also because in Quarks&Leptons of Halzen&Martin they say
<<There is no empirical evidence for the existense of RH neutrinos and it could well be that they do not exist in nature.>>
I have an argument via which i make the assertion that RH neutrinos (and LH antineutrinos) MUST exist, even thought we cannot interact with them and see them. It goes like this:
A neutrino satisfies the dirac equation with zero mass. Solving it, we get four solutions.
2 spinors for the neutrino (RH and LH neutrino)
2 spinors for the antineutrino (RH and LH antineutrino).
If we want to have a complete set of solutions, all 4 spinors must hold (that is, exist). We cannot say that i keep the LH neutrino and throw away the RH one. This argument is the same with the one we make about the negative energy solutions. We cannot just simply say that "E<0 solutions are unacceptable" since the E>0 by themselves don't make a complete set of solutions.
(To be honest i haven't really understood why we MUST have a complete set of solution, but the point is that its true)
So i conclude that RH neutrinos MUST exist.
What do you think?
1) Neutral Pion
It's quark content is written as: [tex]\pi^0=(u\overline{u}-d\overline{d})/\sqrt{2}[/tex]
But the u-quark have a (quite) different mass than the d-quarks. This means that the neutral pion is a superposition of states of different mass??
2) Right-Handed (RH) Neutrinos
First of all, I am talking about SM neutrinos with zero mass! We know that neutrinos interact only via the weak interactions and only with their Left-Handed (LH) component. So, the theory actually predicts that we cannot observe RH neutrinos. Does this mean that they do not exist? I ask this because my proffessor made that assertion, and also because in Quarks&Leptons of Halzen&Martin they say
<<There is no empirical evidence for the existense of RH neutrinos and it could well be that they do not exist in nature.>>
I have an argument via which i make the assertion that RH neutrinos (and LH antineutrinos) MUST exist, even thought we cannot interact with them and see them. It goes like this:
A neutrino satisfies the dirac equation with zero mass. Solving it, we get four solutions.
2 spinors for the neutrino (RH and LH neutrino)
2 spinors for the antineutrino (RH and LH antineutrino).
If we want to have a complete set of solutions, all 4 spinors must hold (that is, exist). We cannot say that i keep the LH neutrino and throw away the RH one. This argument is the same with the one we make about the negative energy solutions. We cannot just simply say that "E<0 solutions are unacceptable" since the E>0 by themselves don't make a complete set of solutions.
(To be honest i haven't really understood why we MUST have a complete set of solution, but the point is that its true)
So i conclude that RH neutrinos MUST exist.
What do you think?