- #1
bayners123
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[itex]\pi^0[/itex]s decay to two photons via the EM interaction. The [itex]J^{PC}[/itex] of the pion is [itex]0^{-+}[/itex] and of a [itex]\gamma[/itex] is [itex]1^{--}[/itex].
[itex]\gamma\gamma[/itex] therefore has [itex]J^{PC} = 0^{++}, 1^{-+}, 2^{++}[/itex].
This does not match the pion, so how can this decay occur?
[itex]\gamma\gamma[/itex] therefore has [itex]J^{PC} = 0^{++}, 1^{-+}, 2^{++}[/itex].
This does not match the pion, so how can this decay occur?