- #1
charlie'sthe1
- 2
- 0
hi there, new member and this is a bit off a puzzle to me (this isn't homework its something I am trying to use for a little simulation game haha)
ok so the puzzle involves a ball being projected, i am wanting to find the minumum hight it can travell with the longest distance (does that make sence)
so i started of using suvats
u = 45 (45 sin theta in vertical, 45 cos theta in horizontal)
a (in vertical) = - 9.8
s = ?
t = ?
v = ?
so tried to do a bit of simutationas eqations with the vertical eqation. i reckond that at half the time the ball would be at its greatest, so i put in for t - t=0.5t int the equation s=0.5ut-4.9t^2
i then did a bit of differentation to find a when gradient = 0 and got t and sin theta. made a simulatanios EQ with my horizontal. and got theta = 81.7 DEG
i knew that wasnt right haha
could anybody think of an alternitive way or what i should do? is it solvable even?.. is the Q. understandable? haha (been up a long time)
ok so the puzzle involves a ball being projected, i am wanting to find the minumum hight it can travell with the longest distance (does that make sence)
so i started of using suvats
u = 45 (45 sin theta in vertical, 45 cos theta in horizontal)
a (in vertical) = - 9.8
s = ?
t = ?
v = ?
so tried to do a bit of simutationas eqations with the vertical eqation. i reckond that at half the time the ball would be at its greatest, so i put in for t - t=0.5t int the equation s=0.5ut-4.9t^2
i then did a bit of differentation to find a when gradient = 0 and got t and sin theta. made a simulatanios EQ with my horizontal. and got theta = 81.7 DEG
i knew that wasnt right haha
could anybody think of an alternitive way or what i should do? is it solvable even?.. is the Q. understandable? haha (been up a long time)