New method finding moment of inertia of a soild sphere

jaeoos
Messages
3
Reaction score
0
Q. Show the moment of inertia of sphere is 2/5mR^2
using many different methods.

My professor said he knew 18 different method.
Do you have a new idea?
Tell me anything you know. I hope one of your methods will be the 19th method.
 
Physics news on Phys.org
The inertia for a point mass is I = mr^{2}. If you have a sphere you can treat it as a large number of point masses and add them together as in I = \sum m_{i}r_{i}^{2}. It is probably better to solve this using calculus though. For rotational inertia the equation I = \sum m_{i}r_{i}^{2} is an approximation of I = \int r^{2} dm.

Rotational inertia is also related to kinetic energy. Kinetic energy can be expresses as K = \frac{1}{2} I \omega^{2} where \omega is the angular speed.

I've never heard anyone say that there 18 ways to solve this problem, but I suppose it might depend on what other information you might be given.

hope that helps

-dim
 
Last edited:
It's given a gas of particles all identical which has T fixed and spin S. Let's ##g(\epsilon)## the density of orbital states and ##g(\epsilon) = g_0## for ##\forall \epsilon \in [\epsilon_0, \epsilon_1]##, zero otherwise. How to compute the number of accessible quantum states of one particle? This is my attempt, and I suspect that is not good. Let S=0 and then bosons in a system. Simply, if we have the density of orbitals we have to integrate ##g(\epsilon)## and we have...
Back
Top