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Jontafin410
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Newton's Second law of motion F=ma, where m is the mass of the object that undergoes an acceleration a due to to an applied force F. This law is accurate at low speeds. At high speeds, we use the corresponding formula from Einstein's theory of relativity
F=m[tex]\frac{d}{dt}[/tex]([tex]\frac{v(t)}{\sqrt{1-\frac{v(t)}{c}}[/tex])
Where v(t) is the velocity function and c is the speed of light. Compute
v^2
What has to be "ignored" to simplify this expression to the acceleration a=v'(t) in Newton's second law?
F=m[tex]\frac{d}{dt}[/tex]([tex]\frac{v(t)}{\sqrt{1-\frac{v(t)}{c}}[/tex])
Where v(t) is the velocity function and c is the speed of light. Compute
v^2
What has to be "ignored" to simplify this expression to the acceleration a=v'(t) in Newton's second law?