No. of trials for P>0.99 of at least one basket ball success

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The discussion focuses on calculating the number of trials needed to achieve a probability of at least one basketball success greater than 0.99. The probability of no success in one trial is established as 0.25, leading to the formula for no success in n trials as (0.25)^n. To find the probability of at least one success in n trials, the equation 1 - (0.25)^n ≥ 0.99 is used. Solving this inequality shows that n must be at least 4 to meet the requirement. The conclusion confirms that the calculation is correct.
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Homework Statement


upload_2017-11-21_18-36-58.png


Homework Equations

The Attempt at a Solution


Probability of getting no success in one trial ##P( \bar p) = 1 – P (p) = 0.25 ##

Probability of getting no success in n trials ##P_n( \bar p) = (1 – P (p) )^n= (0.25)^n ##

Probability of getting one success in n trials ##P_n( 1p) = 1-(1 – P (p) )^n=1- (0.25)^n ##

We have,

## 1- (0.25)^n \geq 0.99

\\ n \geq 3.3 ##

So, necessary n = 4
Is this correct?
 

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I'd say yes, correct.
 
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