No one has figured this out Problem I'm stuck

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In summary, a 2.0 kg block was placed on a compressed vertical spring that was compressed by 0.050m. When released, the spring propelled the block vertically upward. After rising 0.60m, the block had a velocity of 1.7 m/s. To determine the original potential energy in the spring, an energy balance equation was used, which combined the formulas for potential energy (PE) and kinetic energy (KE) to form the conservation of energy equation (E = 0.5mv^2 + 0.5kx^2).
  • #1
dken221
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a block of mass 2.0 kg is placed on a compressed vertical spring that is compressed .050m. (The spring and the block are not attached) The spring is released, and it propels the block vertically upward. when the block has risen .60m abovie its initial position, its velocity is 1.7 m/s. how much potential energy was originally in the spring?
 
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  • #2
Set up an energy balance equation. Then go from there.
 
  • #3
First hint look into conservation of energy.

Here are some formulas to look into

PE=.5kx^2

k=spring constant
x=position

KE=.5mv^2

Combine them to form conservation of energy

E=.5mv^2+.5kx^2
 

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