Node at a closed end and an antinode at a open end of a tube

In summary, the presence of a node at the closed end of an air column and an antinode at the open end is caused by the behavior of air particles in that specific location. This does not change as the wave oscillates, as the closed end does not allow for displacement while the open end does.
  • #1
Cardinalmont
What causes there to be a node at a closed end of an air column and an antinode at the open end of a air column? Why doesn't it change as the wave oscillates?
 
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  • #2
I believe you are asking about displacement nodes and antinodes. Right at the closed end, a sliver of air dx cannot oscillate because it has nowhere to go which causes the pressure to rise and drop above as far as it will ever go above ambient pressure. You have a displacement node and a pressure antinode.

At the open end, the opposite happens; the sliver of air is free to oscillate at maximum displacement while the pressure is fixed at its ambient (atmospheric) value. You have a displacement antinode and a pressure node.
 

FAQ: Node at a closed end and an antinode at a open end of a tube

What is a node?

A node is a point in a standing wave where the amplitude is always zero. This means that there is no displacement at this point, and the particles in the medium are not moving.

What is an antinode?

An antinode is a point in a standing wave where the amplitude is at its maximum. This means that the particles in the medium are experiencing maximum displacement at this point.

Why is there a node at a closed end of a tube?

When a wave reflects off of a fixed end, the reflected wave interferes with the incident wave. This interference results in a node at the fixed end, as the reflected wave has an opposite phase to the incident wave.

Why is there an antinode at an open end of a tube?

When a wave reflects off of a free end, the reflected wave interferes with the incident wave. This interference results in an antinode at the free end, as the reflected wave has the same phase as the incident wave.

How does the placement of nodes and antinodes affect the frequency of a standing wave?

The distance between nodes and antinodes determines the wavelength of the standing wave, which in turn affects the frequency of the wave. The shorter the distance between nodes and antinodes, the shorter the wavelength and higher the frequency. Conversely, a longer distance between nodes and antinodes results in a longer wavelength and lower frequency.

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