Normal Force, Static and Kinectic Friction.

[stillborndesire]

1.
A block whose weight is 41.0 N rests on a horizontal table. A horizontal force of 48 N is applied to the block. The coefficients of static and kinetic friction are 0.650 and 0.420 N, respectively. Will the block move under the influence of the force, and, if so, what will be the block's acceleration? (If not, enter 0.)



2. W (weight) = mg (mass)(9.8m/s^2)= normal force (FN), FsMAX (maximum static frictional foroce) = μs (coefficient of static friction) x FN, Ax (acceleration in x component) = Fk (kinetic frictional force) / m = ( μk x FN) / m. μk = coefficient of kinetic friction

Attempt 1)
3.
Attempt 1)
FsMAX = μs x FN
= (.650 x 41)
= 26.65
48 (Horizontal force) > 26.65 --> acceleration will occur
Ax = Fk/m
= μk x Fn / m
= (.420 x (41 - 26.65) ) / (41 / 9.8)
= (.420 x 14.35) / 4.1836
= 1.44 m/s ^2
----------------------
Attempt 2)
Ax = Fk/m
= μk x Fn / m
= (.420 x (48 - 26.65) ) / (41 / 9.8)
= (.420 x 21.35) / 4.1836
= 2.14 m/s ^2

 

[G01]

Remember that the acceleration will be given by Newton's Second Law:

$$a=\frac{\Sigma F}{m}$$

What is $$\Sigma F$$?

 

[m2003]

The block will move under the influence of the force, with an acceleration of either 1.44 m/s^2 or 2.14 m/s^2, depending on the starting position of the block. The coefficients of static and kinetic friction play a crucial role in determining the block's movement. The maximum static frictional force must be overcome by the applied force in order for the block to start moving. Once the block is in motion, the kinetic frictional force will be less than the maximum static frictional force, resulting in a lower acceleration. This illustrates the importance of understanding the different types of friction and how they affect the movement of objects. As a scientist, it is important to accurately calculate and consider these factors in order to make accurate predictions and explanations about the behavior of objects in different situations.