Normal Mode calculation steps

In summary, the Normal Mode calculation steps involve the following key processes: first, construct the system's potential energy matrix based on the forces acting on atoms; next, derive the Hessian matrix from the second derivatives of the potential energy; then, diagonalize the Hessian matrix to find the eigenvalues and eigenvectors, which correspond to the normal frequencies and modes of vibration; finally, analyze the results to interpret the physical behavior of the system in its normal modes.
  • #1
vgarg
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Can someone please explain me the steps of calculation of X1:X2 after putting in the lower value of W^2 in equation 9.9 in "Riley, Hobson, Bence - Mathematical Methods for Physics and Engineering 2006 - pg 319"? I have attached the page as a PDF file.
Thank you.
 

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  • #2
A and B are matrices you know, and ##\,omega## is a number that you know, so you can plug them all in and you get like like ##Cx=0## for some matrix ##C## that you know. You might at first guess that gives you two equations and two unknown (##x## is a vector of 2 dimensions, the 0 on the right side is also a vector of 2 dimensions so you get two equations) but if ##x## is a solution so is ##\alpha x## for any scalar ##\alpha##, which means the two equations are not independent, and there are infinite solutions. So all you can do is express one variable in terms of the other which is the same as computing their ratio
 
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  • #3
Office_Shredder said:
A and B are matrices you know, and ##\,omega## is a number that you know, so you can plug them all in and you get like like ##Cx=0## for some matrix ##C## that you know. You might at first guess that gives you two equations and two unknown (##x## is a vector of 2 dimensions, the 0 on the right side is also a vector of 2 dimensions so you get two equations) but if ##x## is a solution so is ##\alpha x## for any scalar ##\alpha##, which means the two equations are not independent, and there are infinite solutions. So all you can do is express one variable in terms of the other which is the same as computing their ratio
Thank you very much.
 
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