Normal Zeeman effect of hydrogen atoms

In summary, when specially prepared Hydrogen atoms with their electrons in the 6d state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels, known as the normal Zeeman effect. The largest possible energy difference, ignoring electron spin, is calculated using the formula Delta_E=ml*\mub*B, where \mub=5.7884 eV/T. In part A of the question, the energy difference is found to be 6.599E-4 eV. After a certain period, the electrons return to the 1s ground state in the Hydrogen atoms. In part B, the energy difference between the lowest and highest observed "ground" state in the same magnetic field
  • #1
kraigandrews
108
0

Homework Statement



When specially prepared Hydrogen atoms with their electrons in the 6d state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.

A) Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.28 Tesla?

After a certain period the electrons return to the 1s ground state in the Hydrogen atoms.

B) What will be the energy difference between the lowest and the highest observed "ground" state still in the same magnetic field?



Homework Equations



Delta_E=ml*[itex]\mu[/itex]b*B, where [itex]\mu[/itex]b=5.7884 eV/T

The Attempt at a Solution


for a)
since it is in 6d i think ml=5 then it should just be a plug and chug to get: 6.599E-4 eV but this isn't right. So I am not sure where i went wrong.

for b) I am not sure what to do.
 
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  • #2
If it is 6d, this means that its principle quantum number is 6 and its orbital angular momentum quantum number is 2 (since it goes s=0, p=1, d=2).
So we are given the orbital angular momentum quantum number, so what are the possible values for the magnetic quantum number? And what is the greatest possible difference in ml? (Its not 5).
For b, for the 1s state, think what do we know about the possible values of ml?
 

FAQ: Normal Zeeman effect of hydrogen atoms

1. What is the Normal Zeeman effect of hydrogen atoms?

The Normal Zeeman effect of hydrogen atoms is a phenomenon in which the spectral lines of hydrogen atoms split into multiple lines when subjected to a magnetic field. This splitting is caused by the interaction between the electron's spin and orbital angular momentum in the presence of a magnetic field.

2. How does the Normal Zeeman effect of hydrogen atoms occur?

The Normal Zeeman effect occurs when a hydrogen atom's electron transitions between different energy levels, such as from the ground state to an excited state. The interaction between the electron's spin and orbital angular momentum causes the energy levels to split into multiple levels in the presence of a magnetic field.

3. What causes the splitting of spectral lines in the Normal Zeeman effect of hydrogen atoms?

The splitting of spectral lines in the Normal Zeeman effect is caused by the interaction between the electron's spin and orbital angular momentum in the presence of a magnetic field. This interaction causes the energy levels to split into multiple levels, resulting in the observed splitting of spectral lines.

4. How is the Normal Zeeman effect of hydrogen atoms observed and measured?

The Normal Zeeman effect can be observed and measured using a spectrometer, which is a device that separates light into its individual wavelengths. The spectral lines of hydrogen atoms can then be observed and measured, and any splitting of the lines can be recorded and analyzed to determine the strength of the magnetic field.

5. What are the applications of the Normal Zeeman effect of hydrogen atoms?

The Normal Zeeman effect has various applications in fields such as astronomy, physics, and chemistry. It can be used to study the structure and behavior of atoms and molecules, as well as to measure the strength of magnetic fields. It also has practical applications in the development of technologies such as magnetic resonance imaging (MRI) and atomic clocks.

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