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iamnew said:Homework Statement
The circuit is attached as a jpg image. How can i find the norton equivalent when both current sources and voltage sources are present?
please help
Homework Equations
The Attempt at a Solution
Norton and Thevenin equivalent are two equivalent circuit models that simplify complex circuits into a single equivalent circuit. They are commonly used in circuit analysis and design to make calculations and analysis easier.
The main difference between Norton and Thevenin equivalent is that in Norton equivalent, the equivalent circuit is represented by a current source in parallel with a resistance, while in Thevenin equivalent, it is represented by a voltage source in series with a resistance.
To calculate Norton equivalent, you need to find the Norton current, which is the short-circuit current between the output terminals of the circuit. The Norton resistance is then calculated by dividing the open-circuit voltage by the Norton current. To calculate Thevenin equivalent, you need to find the Thevenin voltage, which is the open-circuit voltage at the output terminals of the circuit. The Thevenin resistance is then calculated by dividing the Thevenin voltage by the short-circuit current.
You should use Norton equivalent when you need to find the current flowing through a specific load in a circuit, while Thevenin equivalent is used when you need to find the voltage across a specific load in a circuit. It ultimately depends on the specific analysis or design problem you are trying to solve.
Yes, you can convert Norton equivalent to Thevenin equivalent and vice versa using a simple conversion formula. To convert Norton to Thevenin, you can use the formula Vth = IN * Rn, where Vth is the Thevenin voltage, IN is the Norton current, and Rn is the Norton resistance. To convert Thevenin to Norton, you can use the formula In = Vth / Rth, where In is the Norton current, Vth is the Thevenin voltage, and Rth is the Thevenin resistance.