Not understanding Hulse Taylor period shift calculation

In summary, the calculation of the period shift for Hulse Taylor PSR 1913+16 is regarded as an indirect proof for gravitational waves. However, there are some discrepancies in the understanding of the graph of cumulative period shift, with the final inspiral being calculated to happen in 300 million years but the cumulative period shift doubling every 10 years. Upon closer examination, it is found that the decrease in period is approximately linear, with its integral being a parabola. This is evidenced by the fact that the differences and second differences of the integrated shift follow the expected pattern for a parabola. It is important to note that while there may be some non-linearity in certain time periods, overall the trend is still consistent with
  • #1
Prometeus
43
3
I have been studying Hulse Taylor PSR 1913+16 calculation of period shift which is regarded as indirect proof for gravitational waves, but I don't understand one thing.
If you look on the graph of Cumulative period shift, around every 10 years the shift doubles.
https://en.wikipedia.org/wiki/File:PSR_B1913+16_period_shift_graph.svg

It is in seconds, so it seems no big deal, but the final inspiral is calculated to happen in 300 millions years, which a lot of time. But when the cumulative period continues to double like every 10 years, the final inspiral would happen much sooner, estimating it certainly at less than 100 000 years.
So what is wrong with my understanding of it? Is the period shift something which has some periodic nature, so the period shift is not always decreasing, but also increasing?

I couldn't find any published detailed description of the calculation and how this would fit both geometrically increasing period shift and 300 millions year to inspiral. It would be helpful, if somebody could link detailed and complete calculation.
 
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  • #2
It does not follow an exponential distribution, it is a parabola.

The decrease in period is approximately linear (at least within a few decades), so its integral is a parabola.
 
  • #3
mfb said:
It does not follow an exponential distribution, it is a parabola.

The decrease in period is approximately linear (at least within a few decades), so its integral is a parabola.

Im not a math wizard, but it is obviously not linear. Cumulative of linear increase would be a straight line on graph. In reality it is obviously doubling every 10 years so it is not linear.
 
  • #4
Prometeus said:
Im not a math wizard, but it is obviously not linear. Cumulative of linear increase would be a straight line on graph. In reality it is obviously doubling every 10 years so it is not linear.

None of those three things are true. You might want to look at the graph and mfb's message again.
 
  • #5
If it is "obviously doubling every 10 years", which values do you get from the graph for 1984 and 2004? There are 20 years in between, so it should be a factor of 4. Is it?
 
  • #6
mfb said:
If it is "obviously doubling every 10 years", which values do you get from the graph for 1984 and 2004? There are 20 years in between, so it should be a factor of 4. Is it?

OK, looked on it again and you are right, it is not doubling. From 1975 to 1985 was the cumulative period shift around 5 seconds, from 1985 to 1995 it was 15 seconds and from 1995 to 2005 it was 20 seconds. So we can say, that from 1985 to 2005 it was quite linear, but there is significant non linearity in 1975 to 1995. Why is it there? How can it be? It should be perfectly linear, when it should last for 300 millions years.
 
  • #7
I get 0 seconds, 4.5 seconds, 17.5 seconds, and 39 seconds for the integrated shift, respectively. The differences are 4.5 seconds, 13 seconds and 21.5 seconds, and the second differences are 8.5 seconds and 8.5 seconds - they are the same. That is exactly what you expect for a parabola. And the derivative of a parabola is a linear function.

pulsar.png
 

FAQ: Not understanding Hulse Taylor period shift calculation

1. What is the Hulse Taylor period shift calculation?

The Hulse Taylor period shift calculation is a method used in astrophysics to measure and predict the changes in the orbital period of a binary pulsar system. This calculation was developed by Russell Hulse and Joseph Taylor, who won the Nobel Prize in Physics in 1993 for their work on this topic.

2. Why is the Hulse Taylor period shift calculation important?

The Hulse Taylor period shift calculation is important because it provides evidence for the existence of gravitational waves, as predicted by Albert Einstein in his theory of general relativity. This calculation also helps us understand the behavior of binary pulsar systems and how they evolve over time.

3. How is the Hulse Taylor period shift calculation performed?

The Hulse Taylor period shift calculation involves measuring the changes in the orbital period of a binary pulsar over time. This is done by observing the pulsar's radio emissions and analyzing the Doppler shifts caused by the pulsar's motion around its companion star.

4. What is the significance of the Hulse Taylor period shift calculation?

The Hulse Taylor period shift calculation has provided strong evidence for the existence of gravitational waves and has helped validate Einstein's theory of general relativity. It has also contributed to our understanding of the behavior of binary pulsar systems and their role in the study of the universe.

5. Are there any challenges or limitations to the Hulse Taylor period shift calculation?

One challenge of the Hulse Taylor period shift calculation is the need for long-term observations of a binary pulsar system, which can span decades. This requires a significant amount of resources and can be affected by external factors such as changes in the Earth's atmosphere. Additionally, this calculation only applies to binary pulsar systems and cannot be used to study other types of celestial objects.

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