Nuclear equations and conservation of charge

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In the discussion on nuclear equations and conservation of charge, participants clarify why beta decay equations are typically written without a positive charge on the nitrogen product. The consensus is that the equations focus on nuclear particles rather than atomic charge, making the notation of nitrogen as ^{14}_{7}N appropriate without a "+" sign. The charge is inherently accounted for in the atomic number of nitrogen, which is 7. This notation aligns with standard practices in nuclear physics, emphasizing the conservation of charge during the decay process. Overall, the discussion highlights the importance of understanding the context of nuclear versus atomic representations in these equations.
tsutsuji
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Do you know why in most textbooks, like on http://www.lbl.gov/abc/Basic.html or http://books.google.com/books?id=xD0AwBQECasC&pg=PA196 beta decay equations are written like

^{14}_{6}C\rightarrow^{14}_{7}N+e^{-}+\overline{\nu}_{e}

instead of

^{14}_{6}C\rightarrow^{14}_{7}N^{+}+e^{-}+\overline{\nu}_{e}

Wouldn't the latter be more correct as regards conservation of charge ?
 
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tsutsuji said:
Do you know why in most textbooks, like on http://www.lbl.gov/abc/Basic.html or http://books.google.com/books?id=xD0AwBQECasC&pg=PA196 beta decay equations are written like

^{14}_{6}C\rightarrow^{14}_{7}N+e^{-}+\overline{\nu}_{e}

instead of

^{14}_{6}C\rightarrow^{14}_{7}N^{+}+e^{-}+\overline{\nu}_{e}

Wouldn't the latter be more correct as regards conservation of charge ?

I usually see it written as

^{14}_{6}C\rightarrow^{14}_{7}N+^{ 0}_{-1}e+^{0}_{0}\overline{\nu}_{e}
 
The equation is discussing the nucleus, not the atom. So no need to put a + in front of the N.
 
completely agree with Vanadium... the + is included in the 7 of Nitrogen
 
Thanks for all the replies.
 

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