Number of rolls of a die to get a particular #

  • Thread starter techmologist
  • Start date
In summary, 3 rolls gives you a less than even chance, while 4 rolls gives a greater than even chance.
  • #1
techmologist
306
12
How many rolls of a single die gives you an even chance of rolling, say, a six? Does this problem, as stated, even have a unique answer? Three rolls gives you a less than even chance, while four rolls gives a greater than even chance. It is tempting to solve

(5/6)^x = .5 and get

x = ln 2 / ln (6/5) ~ 3.8

But since the rule that the probability of several independent events is just the product of their individual probabilities only applies for an integral number of events, this answer isn't really justified. All it tells you is that the answer, if there is one, is between 3 and 4.
 
Physics news on Phys.org
  • #2
You have answered the question for yourself. Three is not enough and four is too many, so there is no way to get a probability of exactly one half.
 
  • #3
Right, no single trial is going to give even chances. But in a repeated trial situation, there may be ways to make the chances even. One way would be to use some other randomizer (like random number generator) to decide whether you get 3 or 4 rolls on any particular trial. Actually I guess doing it this way, with the number of rolls being a random variable, really can make a single trial have even chances. But that's getting a little fancy for practical situations. I asked this question because I heard a story about a legendary professional gambler, Titanic Thompson, using this proposition to beat someone out of a fair amount of cash. He allowed the person to alternate rolling three and four rolls, for an average of 3.5 rolls per trial. The person telling it explained that the correct line is 3.8. I wondered how he got that answer. I think the answer depends on the structure of the bet. Do you let the person roll the die three times some fraction of the time and four rolls the other, or one roll and six rolls, two and ten, or whatever? It turns out that when you randomly get 3 or 4 rolls in such a way that chances are even, the average number of rolls is indeed close to 3.8. I haven't tried it yet, but it may turn out that in all these situations, the average number of rolls is close to 3.8. But I really doubt they are all exactly the same. I also thought it was a neat coincidence that naively solving (5/6)^x = .5 gives this answer, because I don't see how that would apply here.
 

FAQ: Number of rolls of a die to get a particular #

How many rolls of a die are needed to get a particular number?

The number of rolls needed to get a particular number on a die depends on the probability of rolling that number. For a standard 6-sided die, the probability of rolling any number is 1/6. This means that on average, it would take 6 rolls to get a particular number. However, this is not a guarantee and it is possible to roll the same number multiple times in a row.

Is there a way to guarantee rolling a particular number on a die?

No, there is no way to guarantee rolling a particular number on a die. Each roll of a die is independent of the previous roll and is based on probability. Even if you roll the same number multiple times in a row, there is still a chance that you may not roll that number again.

What is the probability of rolling a particular number on a die in a specific number of rolls?

The probability of rolling a particular number on a die in a specific number of rolls can be calculated using the binomial distribution formula. This takes into account the number of rolls, the probability of rolling the number, and the number of successes desired. For example, if you want to roll a 3 on a die in 10 rolls, the probability would be (10 choose 1) * (1/6)^1 * (5/6)^9, which is approximately 0.323 or 32.3%.

How does the number of sides on a die affect the number of rolls needed to get a particular number?

The number of sides on a die does not significantly affect the number of rolls needed to get a particular number. As stated earlier, for a standard 6-sided die, the probability of rolling any number is 1/6. This means that it would take an average of 6 rolls to get a particular number. This holds true for any number of sides on a die. However, a die with more sides may have a slightly lower or higher probability of rolling a specific number.

Is there a mathematical formula for predicting the number of rolls needed to get a particular number on a die?

Yes, there is a mathematical formula for predicting the number of rolls needed to get a particular number on a die. This is known as the expected value and is calculated by multiplying the number of rolls by the probability of rolling the desired number. For example, if you want to roll a 4 on a standard 6-sided die, the expected value would be 6 * (1/6), which is equal to 1. This means that on average, it would take 1 roll to get a 4 on a 6-sided die. However, as stated before, this is not a guarantee and it is possible to roll the same number multiple times in a row.

Similar threads

Replies
3
Views
2K
Replies
29
Views
3K
Replies
41
Views
4K
Replies
10
Views
2K
Replies
13
Views
4K
Back
Top