- #1
DeanBH
- 82
- 0
how do i find the number of roots for a curve that has dy/dx
2x^4 -20x^2 + 50.
if i substitute y=x^2 and use the discriminant formula i get
b^2 - 4ac = 400 - 4 x 2 x 50
= 400 - 400
= 0
This way says there 1 root, answers say it has 2. Which method am i meant to use for this?
if i factorise i get 2(y-5)^2
which is also 1?
2x^4 -20x^2 + 50.
if i substitute y=x^2 and use the discriminant formula i get
b^2 - 4ac = 400 - 4 x 2 x 50
= 400 - 400
= 0
This way says there 1 root, answers say it has 2. Which method am i meant to use for this?
if i factorise i get 2(y-5)^2
which is also 1?
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