- #1
shakgoku
- 29
- 1
Homework Statement
what happens to the number of solutions of the equation
[tex]x = \tanh(\beta x) [/tex]
When
[tex] \beta[/tex] is varied from [tex]\frac{1}{2} [/tex] to [tex] \frac{3}{2} [/tex]
[/tex]
a) unchanged
b) increase by 1
c) increase by 2
d) increase by 3
Homework Equations
[tex] \tanh(ax) =.... -\frac{17}{315} \, a^{7} x^{7} + \frac{2}{15} \, a^{5} x^{5} -
\frac{1}{3} \, a^{3} x^{3} + a x[/tex]
[tex] tanh(ax)= \frac{e^{ax}-e^{-ax}}{e^{ax}+e^{-ax}}
[/tex]
The Attempt at a Solution
Tried to Apply the two above formulas without any success. This is an examination question and too bad, Graphing and programming calculators are not allowed :(