- #1
tomas krchnak
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Homework Statement
There is a escalator and 2 persons move up it. A takes 50 steps and B takes 75 steps while the escalator is moving up. Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps, find the no. of steps in the escalator that is possible to see while it is staionary.?
Homework Equations
The Attempt at a Solution
v is the speed of persons (A=1v, B=3v)
x is the number of stairs
y is the speed of escalator
so:
50/v=(x-50)/y
75/3v=(x-75)/y
I make from that:
(50y/v)+50=x
(25y/v)+75=x
and then i remove fractions and have system of equations
50y+50v=xv
25y+75v=xv *(-2) equivalent adjustment
50y+50v=xv
-50y-150v=-2xv
-100v=-xv
-100=-x
x=100
Now I got the number of steps so if I do 100/2=50 is the number of steps we can see if it is stationary.
I just want to ask if is everything right.
And.. I´m not good in english so there are many mistakes in it, so sorry