MHB Number of Ways to Select 3 Men & 3 Women from 5 Married Couples

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To determine the number of ways to select 3 men and 3 women from 5 married couples with exactly 2 married couples, first select 2 couples from the 5. Next, choose 1 man from the remaining 3 men, ensuring he is not married to any of the selected women. Additionally, select 1 woman from the 2 women not married to the chosen man. This structured approach ensures compliance with the requirement of including exactly 2 married couples in the selection.
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Find the number of ways of selecting 3 men and 3 women from 5 married couples such that there are exactly 2 married couples.

I need the reasoning
 
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First you select two couples out of five. Then you select one man out of the remaining three and one of the two women who are not his spouse.
 
Punch said:
Find the number of ways of selecting 3 men and 3 women from 5 married couples such that there are exactly 2 married couples.
I need the reasoning
Choose three wives. From their husbands choose two. Then choose one of the other men not married to any of the three chosen wives.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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