- #1
homim4
- 2
- 0
Hi,
I have faced the following question. In our lab we perform different measurements on Transistors. We program a scope and that controls the tests. For one of our tests we would like to calculate the total charge Q. Mathematically this is given by
Q=∫ dt i(t), where i(t) is given by i(t) = v(t)/R, i(t)= current, v(t)=voltage, R= resistivity ( constant value), for a time interval [t1, t2]
We cannot measure i(t) directly but we can measure v(t). This means
Q=∫dt v(t)/R.
We have noticed the following
1. if we define Q1 = ∫dt ( v(t)/R)
2. or if we define Q2= (∫dt v(t))/R
Mathematically these two integrals should produce the same result. But we see completely different results. I wonder if this depends on the numerical methods used in integration or has another reason.
Thank you for your help.
I have faced the following question. In our lab we perform different measurements on Transistors. We program a scope and that controls the tests. For one of our tests we would like to calculate the total charge Q. Mathematically this is given by
Q=∫ dt i(t), where i(t) is given by i(t) = v(t)/R, i(t)= current, v(t)=voltage, R= resistivity ( constant value), for a time interval [t1, t2]
We cannot measure i(t) directly but we can measure v(t). This means
Q=∫dt v(t)/R.
We have noticed the following
1. if we define Q1 = ∫dt ( v(t)/R)
2. or if we define Q2= (∫dt v(t))/R
Mathematically these two integrals should produce the same result. But we see completely different results. I wonder if this depends on the numerical methods used in integration or has another reason.
Thank you for your help.