- #1
Jasones
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So, in
Nu=[itex]\frac{hD}{k}[/itex]
h is the heat transfer coefficient, and D is the diameter of the pipe in which heat transfer takes place...
..but what are the dimensions of k in terms of mass (M), length (L), time (T) and temperature ([itex]\theta[/itex])?
So far, I've worked out that the units for h are J/(m2 hr C), but I'm having difficulty expressing k in terms of what is given.
Am I wrong is thinking that J/(m2 hr C) can be expressed as W/(m2 K)? I'm thinking that this is relevant to the end units of k, but I am unsure if the dimensions are correct.
Nu=[itex]\frac{hD}{k}[/itex]
h is the heat transfer coefficient, and D is the diameter of the pipe in which heat transfer takes place...
..but what are the dimensions of k in terms of mass (M), length (L), time (T) and temperature ([itex]\theta[/itex])?
So far, I've worked out that the units for h are J/(m2 hr C), but I'm having difficulty expressing k in terms of what is given.
Am I wrong is thinking that J/(m2 hr C) can be expressed as W/(m2 K)? I'm thinking that this is relevant to the end units of k, but I am unsure if the dimensions are correct.
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