- #1
kahless2005
- 46
- 0
Not exactly homework, but it is a problem I'm having...
Im given an ode that reads:
y"-2y'-3y = 6;
[itex]y_c = C_1 * /exp^-x + C_2 * /exp^3x[/itex]
[itex]y_p[/itex] is -2
y(0) = 3
y'(0) = 11
Now I am tasked to find what [itex]C_1[/itex] and [itex]C_2[/itex] are.
I know that y(x) = [itex]y_c + y_p[/itex]
so:
y = [itex]C_1 * /exp^-x + C_2 * /exp^3x[/itex] - 2
and
y' = [itex]-C_1 * /exp^-x + 3 * C_2 * /exp^3x[/itex]
The book defines the answers as:
[itex]C_1[/itex] = 1 and [itex]C_2[/itex] = 4
Yet when I work it out, I've gotten [itex]C_1[/itex] = 2 and [itex]C_2[/itex] = 3.
What am I doing wrong?
NOTE: I hope I did the itex right... my computer isn't showing them...
Im given an ode that reads:
y"-2y'-3y = 6;
[itex]y_c = C_1 * /exp^-x + C_2 * /exp^3x[/itex]
[itex]y_p[/itex] is -2
y(0) = 3
y'(0) = 11
Now I am tasked to find what [itex]C_1[/itex] and [itex]C_2[/itex] are.
I know that y(x) = [itex]y_c + y_p[/itex]
so:
y = [itex]C_1 * /exp^-x + C_2 * /exp^3x[/itex] - 2
and
y' = [itex]-C_1 * /exp^-x + 3 * C_2 * /exp^3x[/itex]
The book defines the answers as:
[itex]C_1[/itex] = 1 and [itex]C_2[/itex] = 4
Yet when I work it out, I've gotten [itex]C_1[/itex] = 2 and [itex]C_2[/itex] = 3.
What am I doing wrong?
NOTE: I hope I did the itex right... my computer isn't showing them...