Observer Inside Collapsing Shell

In summary, the conversation discusses the collapse of a spherically symmetrical thin shell of dust under its own gravity. The shell has a total mass M and starts collapsing from a rest state with a diameter much larger than its Schwarzschild radius. The observer at the center of the shell has a clock and a flashlight, and can make measurements until he is absorbed by the collapsing shell. One possible measurement he can make is the velocity of the inner wall of the shell, but there is no single well-defined answer to this measurement. As the shell collapses, the observer will observe a blueshift in the light signals from buoys inside the shell. When the shell collapses past the buoys, the observer will still receive their light signals before
  • #1
Tomas Vencl
66
13
TL;DR Summary
Inside observer view of a collapsing shell
let's consider spherically symmetrical thin shell of dust, which is collapsing under its own gravity. There are no other forces as pressure or so except gravity, and particles of shell (dust) are in free fall. The shell has total mass M and collapse starts from rest state with diameter of the shell much larger than its Schwarzschild radius. During all collapse the symmetry remains.
Now consider observer (a) with negligible mass in the center of the shell. The observer has a clock and measures its propper time t(a). The observer also has a flashlight, and can send signals and receive reflected signals from inner wall of the shell.

Until the observer is absorbed (collapsed) by the shell, he is still in flat spacetime and he can make some measurements.
If he will measure (or calculate) the "velocity" of inner wall of collapsing shell (meaning dr/dt(a) ,what he will measure/calculate ? Mainly after the shell passes the Schwarzschild radius ? Does the defined "speed" exceeds c, or what are the limits ?
Or generally, what observer (a) can see during collapse ?
 
  • Like
Likes timmdeeg
Physics news on Phys.org
  • #2
Tomas Vencl said:
Until the observer is absorbed (collapsed) by the shell, he is still in flat spacetime and he can make some measurements.
Yes, but the flat spacetime region he is in does not include the shell itself, so he cannot apply the rules of flat spacetime (or the implications those rules have for measurements he makes) to any measurements that involve the shell.

Tomas Vencl said:
If he will measure (or calculate) the "velocity" of inner wall of collapsing shell (meaning dr/dt(a) ,what he will measure/calculate ?
You would have to specify a particular measurement procedure he is going to use. There is no single well-defined answer.

Tomas Vencl said:
what observer (a) can see during collapse ?
Probably the best single observation to describe is the frequency shift he observes of light signals coming from the shell. This will be a blueshift, increasing without bound as the shell approaches him.
 
  • #3
PeterDonis said:
You would have to specify a particular measurement procedure he is going to use. There is no single well-defined answer.
Thank you.
I am thinking about next procerure:
At the beginning there is a line of the synchronized buoys in the region inside shell. Line is oriented radially and starts in the centre. Distances between buoys are regular, and matches to radial distance in flat area. Each buoy is continuously emitting signal, and is designed to stop the emitting while in contact with collapsing shell.
Observer receives signals from buoys, and while signal from apropriate buoy stops than he is comparing with his proper time t(a) . So he can calculate required dr/dt(a).
Will he catch the end of the signals from all buoys, before he is hiting by shell ? Or at some time he catch the end of signal from some buoy (not his nearest) and than is crashed by shell ? Or other scenario ?
 
  • #4
So the buoys stop transmitting when the inner surface of the shell collapses past them? In that case, an observer at the center will always receive the light from each buoy before the shell reaches him - although the delay will tend to zero as the shell collapses.
 
  • Like
Likes PeterDonis
  • #5
Ibix said:
an observer at the center will always receive the light from each buoy before the shell reaches him - although the delay will tend to zero as the shell collapses.
Also, the time by his clock between signals from successive buoys will tend to zero as the shell collapses (this corresponds to the blueshift that I mentioned before).
 
  • #6
Interesting gedankenexperiment!
Let's assume that radial thickness of shell and size of observer are almost negligible compared to the Schwarzschildradius of M.
What experiences the observer in the moment and later when the collapsing shell is within it's Schwarzschildradius 2GM (c=1) and a black hole is formed?
Does the spacetime inside change from flat to curved within this moment?
 
  • #7
timmdeeg said:
What experiences the observer in the center when the collapsing shell is within it's Schwarzschildradius 2GM (c=1) and a black hole is formed?
Nothing.

timmdeeg said:
Does the spacetime inside change from flat to curved within this moment?
No. The entire spacetime region inside the shell is flat. The observer in the center only sees a change in his local spacetime geometry when the shell reaches him.
 
  • Like
Likes timmdeeg

FAQ: Observer Inside Collapsing Shell

What is the Observer Inside Collapsing Shell?

The Observer Inside Collapsing Shell is a thought experiment in physics that explores the concept of an observer inside a collapsing spherical shell. It was first proposed by physicist Albert Einstein in 1916.

How does the Observer Inside Collapsing Shell thought experiment work?

In this thought experiment, the observer is placed at the center of a spherical shell that is collapsing under its own gravity. The observer is surrounded by a vacuum and cannot interact with the outside world. This scenario allows for the exploration of the effects of gravity on an observer in a closed system.

What is the significance of the Observer Inside Collapsing Shell thought experiment?

This thought experiment is significant because it demonstrates the effects of gravity on an observer in a closed system, which is a fundamental concept in general relativity. It also highlights the concept of a singularity, where the laws of physics break down and cannot accurately describe the behavior of matter.

What are the implications of the Observer Inside Collapsing Shell thought experiment?

The implications of this thought experiment are still being explored by physicists. It has led to further research on the behavior of matter and gravity in extreme conditions, such as black holes. It also raises questions about the nature of time and space in the presence of strong gravitational forces.

Can the Observer Inside Collapsing Shell thought experiment be tested in real life?

Currently, it is not possible to replicate this thought experiment in real life. However, scientists have conducted experiments using analog systems, such as fluids and electromagnetic fields, to simulate the effects of gravity on an observer in a closed system. These experiments have provided valuable insights into the behavior of matter and gravity in extreme conditions.

Similar threads

Back
Top