Obtaining Differential Equations with Solution

In summary, the equations given are used to find the family of circles that are tangent to the x-axis. In part (a), the equations are used to eliminate the arbitrary constants x0 and r, while in part (b), the equation is used to eliminate x0. This results in a first order ODE for part (b) and a second order ODE for part (a).
  • #1
cheatmenot
4
0
(a) all circles tangent to x-axis?? with answer on the book [1+(y^{2})^2]^3=[yy''+1+(y')^2]^2

(b) all circles with fixed radius r and tangent to x-axis??

Thanks a bunch!
 
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  • #2
I have moved your thread here to our Differential Equations forum.

(a) Can you begin by giving the family of circles tangent to the $x$-axis?
 
  • #3
cheatmenot said:
(a) all circles tangent to x-axis?? with answer on the book [1+(y^{2})^2]^3=[yy''+1+(y')^2]^2

(b) all circles with fixed radius r and tangent to x-axis??

Thanks a bunch!

(a) The equation of a circle with center at $(x_0,y_0)$ and radius $r$ is: $$(x-x_0)^2+(y-y_0)^2=r^2$$
Since the circles should tangent to the $x-$axis, $y_0= \pm r$.
Therefore,
$$(x-x_0)^2+(y \mp r)^2=r^2 $$
$x_0$ and $r$ are arbitrary constants and must not appear in ODE which generates the family of the circles. Since there are two arbitrary constants to eliminate, the ODE will be second order.

Differentiating both sides with respect to $x$ we have the following:
$$2(x-x_0)+2(y \mp r)y'=0 $$

Differentiating again with respect to $x$ we have the following:
$$2+2(y')^2+2(y \mp r)y''=0 $$

Now you have to use these equations to get rid of $x_0$ and $r$, or to get rid of $(x-x_0)$ and $(y \mp r)$ by expressing them in terms of $y$ and its derivatives.
(b)The equation of a circle with center at $(x_0,y_0)$ and fixed radius $r$ is: $$(x-x_0)^2+(y-y_0)^2=r^2$$
Since the circles should tangent to the $x-$axis, $y_0= \pm r$.
Therefore,
$$(x-x_0)^2+(y \mp r)^2=r^2 $$
$x_0$ is an arbitrary constant and must not appear in ODE which generates the family of the circles. Since there is only one arbitrary constant to eliminate, the ODE will be 1st order.

Differentiating both sides with respect to $x$ we have the following:
$$2(x-x_0)+2(y \mp r)y'=0 $$

Now you have to use these equations to get rid of $x_0$, or to get rid of $(x-x_0)$ by expressing this in terms of $r$ and of $y$ and its derivatives.
 
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  • #4
mathmari said:
(a) The equation of a circle with center at $(x_0,y_0)$ and radius $r$ is: $$(x-x_0)^2+(y-y_0)^2=r^2$$
Since the circles should tangent to the $x-$axis, $y_0= \pm r$.
Therefore,
$$(x-x_0)^2+(y \mp r)^2=r^2 $$
$x_0$ and $r$ are arbitrary constants and must not appear in ODE which generates the family of the circles. Since there are two arbitrary constants to eliminate, the ODE will be second order.

Differentiating both sides with respect to $x$ we have the following:
$$2(x-x_0)+2(y \mp r)y'=0 $$

Differentiating again with respect to $x$ we have the following:
$$2+2(y')^2+2(y \mp r)y''=0 $$

Now you have to use these equations to get rid of $x_0$ and $r$, or to get rid of $(x-x_0)$ and $(y \mp r)$ by expressing them in terms of $y$ and its derivatives.
(b)The equation of a circle with center at $(x_0,y_0)$ and fixed radius $r$ is: $$(x-x_0)^2+(y-y_0)^2=r^2$$
Since the circles should tangent to the $x-$axis, $y_0= \pm r$.
Therefore,
$$(x-x_0)^2+(y \mp r)^2=r^2 $$
$x_0$ is an arbitrary constant and must not appear in ODE which generates the family of the circles. Since there is only one arbitrary constant to eliminate, the ODE will be 1st order.

Differentiating both sides with respect to $x$ we have the following:
$$2(x-x_0)+2(y \mp r)y'=0 $$

Now you have to use these equations to get rid of $x_0$, or to get rid of $(x-x_0)$ by expressing this in terms of $r$ and of $y$ and its derivatives.

thank you for your answer but as i go over and answer them, i got it really hard in obtaining it.. can you do it for me sir?? i really needed it thanks a lot . .more power i need both ..
 
  • #5
(a) We have the following equations:

$$(x-x_0)^2+(y \mp r)^2=r^2 \ \ \ (1)$$
$$2(x-x_0)+2(y \mp r)y'=0 \ \ \ (2)$$
$$2+2(y')^2+2(y \mp r)y''=0 \ \ \ (3)$$

Since we want to get get rid of $(x-x_0)$ and $(y \mp r)$ we do the following:

At the equation $(3)$ solve for $(y \mp r)$ and replace it at the equations $(1)$ and $(2)$.
Then solve at the equation $(2)$ for $(x-x_0)$ and relace this at the equation $(1)$. What do you get??(b)We have the following equations:

$$(x-x_0)^2+(y \mp r)^2=r^2 \ \ \ (*)$$
$$2(x-x_0)+2(y \mp r)y'=0 \ \ \ (**)$$

Since we want to get rid of $(x-x_0)$ we do the following:

At the equation $(**)$ solve for $(x-x_0)$ and replace it at the equation $(*)$. What do you get??
 
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FAQ: Obtaining Differential Equations with Solution

What is the process for obtaining differential equations with solution?

The process for obtaining differential equations with solution involves first identifying the variables and parameters involved in the system. Then, using any relevant laws or principles, such as Newton's Laws or the Law of Conservation of Energy, the equations can be set up. Finally, the equations can be solved using various methods, such as separation of variables or using a computer program.

What are the different types of differential equations?

There are several types of differential equations, including ordinary differential equations, which involve a single independent variable, and partial differential equations, which involve multiple independent variables. Other types include linear and nonlinear differential equations, as well as first-order and higher-order equations.

How do you know if a solution to a differential equation is correct?

To check if a solution to a differential equation is correct, you can substitute the solution back into the original equation and see if it satisfies the equation. Additionally, solutions can be graphed or compared to known solutions to check for accuracy.

Can differential equations be solved analytically or numerically?

Yes, differential equations can be solved analytically, using methods such as separation of variables or integrating factors, or numerically, using computational methods such as Euler's method or Runge-Kutta methods. The method used depends on the complexity of the equation and the availability of initial conditions.

What are some real-world applications of differential equations?

Differential equations have many practical applications in fields such as physics, engineering, and economics. They are used to model physical systems, such as the motion of objects or the flow of fluids, and to make predictions about their behavior. They are also used in the analysis of economic systems and population dynamics.

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