- #1
cue928
- 130
- 0
I have the following logistics problem that I am stuck about halfway thru:
The time rate of change of a rabbit population P is proportional to the square root of P. At time t=0 (months) the population numbers 100 rabbits and is increasing at the rate of 20 rabbits per month. How many rabbits will there be one year late?
I obtained the equation dy/dt = k*p^.5 I solved for a "k" value of 2, but I do not know where to go from there. How do I account for the 20? I understand that is a rate of change but at what point do you substitute that in the problem?
The time rate of change of a rabbit population P is proportional to the square root of P. At time t=0 (months) the population numbers 100 rabbits and is increasing at the rate of 20 rabbits per month. How many rabbits will there be one year late?
I obtained the equation dy/dt = k*p^.5 I solved for a "k" value of 2, but I do not know where to go from there. How do I account for the 20? I understand that is a rate of change but at what point do you substitute that in the problem?